SCERT Assam Class 6 Mathematics Chapter 4 – “Whole Numbers” Summary & Solutions
SCERT Assam Class 6 Mathematics (English Medium) Chapter 4 – “Whole Numbers” solutions are available at Ospin Academy. We provide SCERT-based textbook solutions, multiple-choice questions (MCQs), and a complete chapter summary to help students in their exam preparation.
📖 Chapter Overview:
This chapter explains the concept of **whole numbers**, their properties, and how they differ from natural numbers.
- Understanding Whole Numbers: Definition and examples.
- Properties of Whole Numbers: Closure, Commutative, Associative, and Distributive properties.
- Operations on Whole Numbers: Addition, subtraction, multiplication, and division.
📌 Exercises Covered in Lesson 4:
- Exercise 4A: Identifying whole numbers and their properties.
- Exercise 4B: Performing operations on whole numbers.
- Exercise 4C: Applying properties of whole numbers in problem-solving.
- Exercise 4D: Real-life applications of whole numbers.
📝 Ospin Academy Resources:
- Complete Solutions: SCERT Assam Class 6 Mathematics Chapter 4 answers.
- MCQs & Additional Questions: Exam-focused multiple-choice questions.
- Clear Explanations: Concepts explained in simple terms.
- Quick Revision Notes: Concise notes for last-minute preparation.
For SCERT Assam Class 6 Mathematics (English Medium) Chapter 4 – “Whole Numbers” solutions, visit Ospin Academy.
Class 6 Maths (English Medium) PDF Solutions 2025-26 | SCERT Assam
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Class 6 Mathematics
Chapter – 4 (Ospin Academy)
Whole Numbers
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Exercise – 4 (A) |
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1. Write the successor of 1, 10, 9999, 100000, 777779.
Ans: The successors are:
1 + 1 = 2
10 + 1 = 11
9999 + 1 = 10000
100000 + 1 = 100001
777779 + 1 = 777780
2. Is there any Natural number which has no successor?
Ans: No, there is no Natural number which has no successor.
3. Write the predecessor of 5, 11, 7779, 1000, 10001.
Ans: The predecessors are:
5 – 1 = 4
11 – 1 = 10
7779 – 1 = 7778
1000 – 1 = 999
10001 – 1 = 10,000
4. Is there any natural number that has no predecessor?
Ans: Yes. The predecessor of the natural number 1 is not a natural number.
5. Is there any largest natural number? Your friend writes a bigger number and claims that number is the largest natural number. How can you convince your friend that he is not correct?
Ans: No, because all the whole numbers are not natural numbers.
6. Are all whole numbers also natural numbers?
Ans: No. Zero (0) is a whole number but not a natural number.
7. Which is the smallest whole number?
Ans: 0 (Zero)
8. Which number can be removed from the collection of Whole Numbers so that the remaining numbers will be a collection of natural numbers?
Ans: 0 (Zero)
9. Can you find the greatest whole number?
Ans: No.
10. Can we find the predecessor of 1 in the collection of whole numbers? If so, what is that?
Ans: Yes. Eg = 0 (Zero).
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Exercise – 4 (B) |
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1. Add on the number line:
(i) 3 + 7
Ans:
(ii) 4 + 8
Ans:
(iii) 4 + 3
Ans:
2. Subtract on the number line:
(i) 5 – 2
Ans:
∴ 5 – 2 = 3
(ii) 8 – 7
Ans:
∴ 8 – 7 = 1
(iii) 6 – 6
Ans:
∴ 6 – 6 = 0
3. Find the product using number line.
(i) 3 × 2
Ans:
∴ 3 x 2 = 6
(ii) 2 × 4
Ans:
∴ 2 x 4 = 8
(iii) 5 x 1
Ans:
∴ 5 x 1 = 5
4. Put (✓) on the correct answer and (x) on the incorrect one.
Draw a number line for whole numbers. On that number line for any two whole numbers.
(i) Sum is possible/not possible.
Ans: ✓
(ii) Difference is possible/not possible.
Ans: x
(iii) Product is possible/not possible.
Ans: ✓
(iv) Division is possible/not possible.
Ans: x
5. How many whole numbers are less than 100?
Ans: 100
6. Which 3 digits whole number has the predecessor as biggest 2 digits number?
Ans: 3 digit whole number = 100 and a biggert 2 digit whole number = 99.
7. In each of the following pairs of whole numbers state which whole number is on the right of the other number on the number line. Also write them with the appropriate sign (>, <) between them.
(a) 100, 99
Ans: 100 is placed on the right of 99 on the number line. 100 > 99.
(b) 911,899
Ans: 911 is placed on the right of 899 on the number line. 911 > 899.
(c) 0, 1
Ans: 1 is placed on the right of 0 on the number line. 0 < 1.
(d) 9999, 10000
Ans: 10000 is placed on the right of 9999 on the number line. 9999 < 10000.
(e) 2111, 1222
Ans: 2111 is placed on the right of 1222 on the number line. 2111 > 1222.
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Exercise – 4 (C) |
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1. Find the product orally. Check the result by actually doing it.
(a) 99 x 25 x 4
Ans: 99 x 25 x 4
= 25 x 4 x 99
= 100 x 99
= 9900
(b) 25 x 8 x 5
Ans: 25 x 8 x 5
= 25 x 5 x 8
= 125 x 8
= 1000
(c) 4 x 45 x 50
Ans: 4 x 45 x 50
= 50 x 4 x 45
= 200 x 45
= 9000
2. Fill in the blank spaces with appropriate number.
(a) 2 x (5 x 7) = 2 x…..+ 2 x……
Ans: 2 x (5 x 7) = 2 x 5 + 2 x 7
(b) 3 x (6 + 8) =….x…….+…. X …..
Ans: 3 x (6 + 8) = 3 x 6 + 3 x 8
(c) ….x (3 + 10) = 2 x…..+…… x10
Ans: 2 x (3 + 10) = 2 x 3 + 2 × 10
3. Verify the Associative Property of addition for the numbers 2, 3 and 4.
Ans: 2, 3, 4
(2 + 3) + 4 = 5 + 4 = 9
2 + (3 + 4) = 2 + 7 = 9
∴ 2, 3, 4, satisfy the law of Addition.
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Exercise – 4 (D) |
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1. Fill in the blanks:
(a) If a whole number is added to 0, the sum remains _____________.
Ans: whole number.
(b) If a whole number is divided by 0, the quotient becomes _____________.
Ans: undefined.
(c) If a whole number is multiplied by 1, the product remains _____________.
Ans: The value of the whole number remains unchanged.
(d) If a whole number is multiplied by 0, the product become _____________.
Ans: 0 (Zero).
(e) If a whole number is divided by 1, the quotient remains _____________.
Ans: Same.
2. Which one is correct?
(a) 4 / 2 = 2 / 4
(b) 99 x 77 = 77 x 99
(c) 9 – 8 = 8 – 9
(d) 0 / 3 = 3 / 0
Ans: (b) 99 x 77 = 77 x 99
3. Which value is undefined?
(a) 0 / 9999
(b) 0 × 0
(c) 1 / 100000
(d) 1 / 0
Ans: (d) 1 / 0
4. Which of the following is correct and name the property used?
(a) 2 x (3 + 5) = 2 x 3 + 5
(b) 4 x (7 x 0) = 4 x 7
(c) 3 + (1 + 2) = (3 + 1) + (3 + 2)
(d) 123 x (500 + 123) = 123 x 500 + 123 x 123
Ans: (d) 123 x (500 + 123) = 123 x 500 + 123 x 123
[Distributivity of Multiplication]
5. Solve the following by using appropriate property and also name the property:
(a) 737 + 263 + 234.
Ans: 737 + 263 + 234
= (737 + 263) + 234 (Associative law of addition)
= 737 + 234
= 1234
(b) 968 × 5 × 200.
Ans: 968 × 5 × 200
= 200 × 5 × 968 (Associative law of addition)
= 1000 × 968
= 968000
(c) 45 x 85 + 45 x 15.
Ans: 45 × 85 + 45 × 15
= 45 × (85+15) (Distributive law for multiplication)
= 45 × 100
= 4500
(d) 999 + 876 + 1.
Ans: 999 + 876 + 1
= 999 + (876 + 1) (Associative law of addition)
= 999 + 877
= 1876
(e) 125 × 576 x 8.
Ans: 125 x 576 x 8
= 125(576 x 8)
= 125(8 x 576) (Associative law of multiplication)
= (125 x 8) x 576
= 1000 x 576
= 576000
(f) 397 x 75 + 25 x 397.
Ans: 397 x 75 + 25 x 397
= 397 x (75 + 25) (Distributive law for multiplication)
= 397 x 100
= 39700
6. (a) Are whole numbers closed under addition? Give one example.
Ans: Yes, eg. 7 + 3 = 10, 3 + 7 = 10
(b) Are whole numbers closed under subtraction? Give one example.
Ans: No. eg. 9 – 5 ≠ 5 – 9
7.(a) Are whole numbers closed under multiplication? Give one example.
Ans: Yes, eg. 3 x 5 = 15, 5 x 3 = 15
(b) Are whole numbers closed under division? Give one example.
Ans: No. eg. 3 ÷ 4 = ¾, 4 ÷ 3 = 4 / 3
8. Zero (0) is the additive identity for whole numbers because – [Choose the correct option and put a tick mark (✔) of the following-]
(a) When any whole number is multiplied by Zero, the product becomes 0.
(b) When any whole number is added to 0, the sum becomes that whole number again.
(c) When any whole number is divided by 0, the quotient becomes undefined.
Ans: (b) When any whole number is added to 0, the sum becomes that whole number again.
9. If the total number of pages in a book is 178, then how many pages will be there in 150 books a such type? [Hint: Use distributive property]
Ans: Total number of pages in a book = 178
∴ Total number of pages in 150 books = 178 x 150
= 26,700
SCERT Assam Class 6 Mathematics Chapter 4 – Whole Numbers FAQs
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